Linear feedback shift register polynomial 3 bit

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Just for fun, let's try it with a mirroring output. In order to obtain this kind of coupled outputs, the taps of the Galois register must be the counterparts of the ones of the Fibonacci register.

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The seed choice is not relevant since it would introduce only a shift in the output. In such a register, all possible states are visited - except the null state, which would make the register collapse in a sequence of 0s. The two types of LFSR produce the same result - minus a reflection and a translation - when the taps are the ones generating a maximally long LFSR.

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